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Si $A={x \in \Re / |x-1| < 2}$, entonces
$\circ sup(A) = 3, inf(A) = 0$
$\circ sup(A) = 3, inf(A) = -3$
$\circ sup(A) = 3, inf(A) = -1$
$\circ sup(A) = 2, inf(A) = -2$